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assignments/2-solution.md
@@ -9,7 +9,62 @@ Chapter 4:
1. Given our discussion of positional numbering systems in Section 4.2.1, see whether you can determine the decimal value of the following numbers:
a. 133 (base 4)
+ - 31 (base 10)
b. 367 (base 8, also called octal)
+ - 247 (base 10)
c. 1BA (base 16, also called hexadecimal. B is the digit that represents 11; A is the digit that represents 10.)
+ - 442 (base 10)
+
+| Base (N) | N^8 | N^7 | N^6 | N^5 | N^4 | N^3 | N^2 | N^1 |
+| ---- | - | - | - | - | - | - | - | - |
+| 2 | 128 | 64 | 32 | 16 | 8 | 4 | 2 | 1 |
+| 4 | 16,384 | 4,096 | 1,024 | 256 | 64 | 16 | 4 | 1 |
+| 8 | 2097152 | 262144 | 32768 | 4096 | 512 | 64 | 8 | 1 |
+| 10 | 10,000,000 | 1,000,000 | 100,000 | 10,000 | 1,000 | 100 | 10 | 1 |
+| 16 | 268,435,456 | 16,777,216 | 1,048,576 | 65,536 | 4,096 | 256 | 16 | 1 |
+
+```irb
+irb(main):025> 8.times.map { |x| 2**x }.reverse
+=> [128, 64, 32, 16, 8, 4, 2, 1]
+irb(main):031> 8.times.map { |x| 4**x }.reverse
+=> [16384, 4096, 1024, 256, 64, 16, 4, 1]
+irb(main):032> 8.times.map { |x| 8**x }.reverse
+=> [2097152, 262144, 32768, 4096, 512, 64, 8, 1]
+irb(main):026> 8.times.map { |x| 10**x }.reverse
+=> [10000000, 1000000, 100000, 10000, 1000, 100, 10, 1]
+irb(main):037> 8.times.map { |x| 16**x }.reverse
+=> [268435456, 16777216, 1048576, 65536, 4096, 256, 16, 1]
+```
+
+ a.
+ | 64 | 16 | 4 | 1 |
+ | -- | -- | - | - |
+ | 0 | 1 | 3 | 3 |
+
+ ```ruby
+ (1*16) + (3*4) + (3*1)
+ => 31
+ ```
+
+ b.
+ | 512 | 64 | 8 | 1 |
+ | --- | -- | - | - |
+ | 0 | 3 | 6 | 7 |
+
+ ```ruby
+ (3*64) + (6*8) + (7*1)
+ => 247
+ ```
+
+ c.
+ | 4,096 | 256 | 16 | 1 |
+ | ----- | --- | -- | -- |
+ | 0 | 1 | B | A |
+ | 0 | 1 | 11 | 10 |
+
+ ```ruby
+ (1*256) + (11*16) + (10*1)
+ => 442
+ ```
Chapter 5: